Question 565377
Let
Present age of Mother = m
Present age of Daughter = d



Mother is twice as old as her daughter
m=2d............(1)


8 yrs from now
Mother will be = m+8
Daughter will be = d+8


Then


she will be twenty yrs. than her daughter
m+8=(d+8)+20
m+8=d+8+20
m+8=d+28
m=d+28-8
m=d+20................(2)
Put the value of m from (1) to (2)
2d=d+20
2d-d=20
d=20
Put the value of d in (1)
m=2d
m=2(20)
m=40




Present age of Mother = m = 40 years old
Present age of Daughter = d = 20 years old