Question 565539
{{{(19x^-3y^-1)/(57x^-4y^-3)}}} 
19/57 can be reduced to 1/3, and using the law of exponents to give us positive exponents
{{{1/3}}}{{{(x^(-3+4)*y^(-1+3))}}} = {{{1/3}}}{{{x*y^2}}}