Question 54294
Solve for x: 2(x+2)=2(y-1)
Step 1:
mult what's inside the brackets:
2x + 4 = 2y - 2
:
Step 2:
subtract 4 from both sides to get x by itself on the left:
2x + 4 - 4 = 2y - 2 - 4
2x = 2y - 6
:
Step 3:
Divide both sides by 2 to get 1x or just x
{{{2x/2}}} = {{{(2y-6)/2}}}
:
Step 4:
2/2 = 1 and 2 goes evenly into 2y and - 6 so you have:
x = y - 3
:
: 
Solve for x: (x+2)/3 + (x-5)/4 = 3.5
{{{(x+2)/3}}} + {{{(x-5)/4}}} = 3.5 
:
Get rid of the denominators, the common denominator is of 3 & 4 is 12. 
Mult every term in the equation by 12 and you have:
4(x+2) + 3(x-5) = 12(3.5)
:
4x + 8 + 3x - 15 = 42
:
7x - 7 = 42
:
7x = 42 + 7
:
7x = 49
:
x = 49/7
:
x = 7
:
Check solution in original equation, by substituting 7 for x:
{{{(x+2)/3}}} + {{{(x-5)/4}}} = 3.5
:
{{{(7+2)/3}}} + {{{(7-5)/4}}} = 3.5 
:
{{{(9)/3}}} + {{{(2)/4}}} = 3.5 
:
you can see 9/3 = 3 and 2/4 = .5 so our solution checks out