Question 565119
Length of picture =			32		
Width =			24		
					
Area =			768		In^2

Let the width of frame be x 															
..										
Area =			768		In^2										
Area of framework =			240	In^2											
Length of picture+width  =32+2x					
width of picture+width= 24+2x											
															
(32+2x	)(24+2x)-240=	768
															
768+64x	+48x+4x^2-240=	768
4X^2+112x-240=	0					
Find the roots of the equation by quadratic formula														
	a=	4	b=	112	c=	-240									
	b^2-4ac=	12544	+	3840											
	b^2-4ac=	16384	
	{{{sqrt(	16384	)}}}=	128							
	{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}														
	{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}														
	x1=(	-112	+	128	)/	8									
	x1=	2													
	x2=(	-112	-128	) /	8										
	x2= 	-30													
	Ignore negative value	

width = 2 inches