Question 564945
I need help on this one please

f(x)= 1/4(x+9)^2+1

I need to find out what the vertex is____
I need to find out what the line of symmentry is _____
I need to find out what is the max/min value of fx is _________
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f(x)= 1/4(x+9)^2+1
Since this parabola opens upward, the vertex will be a minimum value
The function has a minimum at x = -9
f(-9) = 1
So the vertex is (-9,1)
The line of symmetry runs parallel to the y-axis and goes through the vertex (-9,1).  
Therefore the line of symmetry is x = -9
The graph is below:
{{{graph(300,300,-20,10,-10,10,(x+9)^2/4+1)}}}
The minimum value is the vertex (-9,1)
The maximum value is {{{infinity}}}