Question 564936
My question is 1/3(4z-3)=4x-5. I have the answer as z=3x-3 from the book, but I don't know why. I can do distributive, and communitive property to solve for a variable in an equation with out an equal sign in the middle like:5(y+6)-4(1-y) is 9y+26, but I don't know what to do when there is an equal sign in the equation; unless it's something like solve for x: 4x+12=4+24. 4x=4+12  4x=16 x=4.
We are trying to solve for z in terms of x
1/3(4z-3)=4x-5
The first step is to multiply both sides by 3:
4z - 3 = 12x - 15
Add 3 to both sides:
4z = 12x - 12
Now divide by 4 to get z by itself:
z = 3x - 3