Question 564878
1) (3x)/(2x)-3+3x+(6/2)x^2+x-6=3/2-9+4x+3x^2=-15/2+4x+3x^2
2) This second answer depends on how you group the division in the second term. Since you didn't use parentheses I'll show you how to do it one way, and you can do it the other way if you need to; [a^2/b]-[b/b^2]/a-a=a^2/b-1/(ba)-a {make a common denominator if you wish}