Question 564717
The ball starts with zero velocity ({{{v=0}}})and accelerates by 32 ft/s each second. At any time, {{{t}}} ,  during the fall, the velocity in ft/s is
{{{v=32t}}} and the distance covered until that time, in feet, is
{{{d=(1/2)32t^2}}} --> {{{d=16t^2}}}
When the ball reaches the ground,
{{{288=16t^2}}} ---> {{{288/16=t^2}}} ---> {{{18=t^2}}} ---> {{{t=sqrt(18)}}}= approx. 4.24 seconds