Question 564752
in a car race, the speed of one car is 120kph and the other car is 105kph. if the faster car finished the race 20mins before the slower one, what was the distance of the race?
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let x=distance
distance/speed=travel time
x/105-x/120=20 min=1/3 hr
LCD: (105)(120)
120x-105x= (105)(120)/3
15x= (105)(120)/3
45x= (105)(120)
x= (105)(120)/45
x=280 
ans:
distance of the race=280 km