Question 564240
 How do I find three consecutive odd integers such that three times the second minus the third is 11 more than the first?
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
2(2x+1)-(2x+3) = 2x-1+11
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4x+2-2x-3 = 2x+10
2x - 1 = 2x + 10
-1 = 10
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The conditions are contradictory.
No solution.
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Cheers,
Stan H.