Question 564236
Let ƒ(x) = 3x^2 – 2x and g(x) = x – 6.
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(f/g)(-1)= = f(-1)/g(-1)
= [3(-1)^2-2(-1)]/[-1-6]
= [3*1+2]/[-7]
= -5/7
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solve equations:
(4x-3)^3/2=8 
(4x-3) = 8^(2/3)
(4x-3) = 2^2
4x-3 = 4
4x = 7
x = 7/4
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(-2-x)^0.5-x = 2
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sqrt(-2-x) = x +2
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Square both sides: 
-2-x = x^2+4x+4
x^2+5x+6 = 0
Factor:
(x+3)(x+2) = 0
x = -2 or x = -3
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Checking those "answers":
(-2-x)^0.5-x = 2
Check x = -2:
(-2+2)^(0.5) +2 = 2
sqrt(0) + 2 = 2
2 = 2
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Check x = -3
(-2+3)^(0.5) + 3 = 2
sqrt(1)+3 = 2
4 = 2
False
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Only solution: x = -2
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Cheers,
Stan H.
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