Question 564026
sqrt(1240/c)=3963
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square both sides to get:
(1240/c) = 3963^2
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c = 1240/3963^2
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c = 7.8954^10^-5
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Checking:
sqrt[(1240/(1240/3963^2)] = 3963
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[(1240/(1240/3963^2)] = 3963^2
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(1240) = [1240/3963^2][3963^2]
1240 = 1240
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Cheers,
Stan H.