Question 563740
{{{f(x) = 25x^2+10x+1}}} Rewrite this as:
{{{y = 25x^2+10x+1}}}
To get y = 1 as you did, you must have let x = 0, why? because:
{{{y = 25(0)6+10(0)+1}}}
{{{y = 1}}} 
So the ordered pair is: (0, 1)
And if you solved this quadratic equation, you would get:
{{{y = 25x^2+10x+1}}} Set y = 0.
{{{25x^2+10x+1 = 0}}} Factor the left side.
{{{(5x+1)(5x+1) = 0}}} so...
{{{x = -1/5}}} which is a double solution.
So when {{{y = 0}}}, {{{x = -1/5}}}, the ordered pair would be: ({{{-1/5}}},{{{0}}})
But note that there is an infinite number of ordered pairs that satisfy this equation.