Question 563746
I need to graph this
f(x)=3x^2-18x+2
Since this is a second degree equation, the graph is a parabola.
complete the square
y=3(x^2-6x+9)+2-27
y=3(x-3)^2-25
This is an equation of a parabola of the standard form: y=A(x-h)^2+k, with (h.k) being the (x,y) coordinates of the vertex.
For given parabola:
Vertex:(3,-25)
axis of symmetry: x=3
Parabola opens upwards (lead coefficient>0)
y-intercept
set x=0
f(0)=3(3)^2-25=27-25=2
This gives you  points at (0,2) and (6,2) because of axis of symmetry.
You now have all the information you need to graph the given function