<PRE><B>Question 563774</B>
A box of 40 coins contains nickels, dimes, and quarters. The total value of the coins is $4.00. If there were 3 times as many nickels, half as many dimes, and 6 more quarters, the value of the coins would be $5.50 How many quarters are in the box?
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Equations:
n  +  d  + q  = 40 coins
5n +10d +25q = 400 cents
3(5n)+5d+25(q+6) = 550 cents
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Solve the system by any means to get:
# nickels = 12 
# dimes   = 24   
# quarters =  4
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Cheers,
Stan H. </PRE>