Question 54206
A CIRCLE WITH A DIAMETER OF 14 INCHES HAS A CIRCUMFERANCE OF 2*PI*R OR

2*3.14*7=43.98 INCHES THEREFORE IT TAKES 5280*12/43.98=63,360/43.98=1440.6548  REVOLUTIONS TO COVER 1 MILE.

ASSUMING THE CIRCUMFERANCE IS WOEN DOWN 1 INCH THEN WE HAVE 43.98-1=42.98 INCH CIRCUMFERANCE THUS 63,360/42.98=1474.174 REVOLTIONS TO COVER 1 MILE.

THUS THE LOSS OF 1 INCH REQUIRES THE WHEEL TO MAKE AN ADDITIONAL 1474.174-1440.5448=33.6292 REVOLUTIONS TO COVER 1 MILE.