Question 563407
Assuming (h,k) is the center of the circle, complete the square:


*[tex \LARGE x^2+y^2+16x-4y+59 = (x+8)^2 + (y-2)^2 - 9 = 0]


*[tex \LARGE (x+8)^2 + (y-2)^2 = 9]


The coordinates of the center are (-8,2).