Question 563489
Let 
First integer = {{{x+1}}}
Second integer={{{x+2}}}
Third integer = {{{x+3}}}
Fourth integer = {{{x+4}}}


Given
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The sum of the first three is 54 more than the fourth.
{{{(x+1)+(x+2)+(x+3)=(x+4)+54}}}
{{{x+1+x+2+x+3=x+4+54}}}
{{{3x+6=x+58}}}
{{{3x-x=58-6}}}
{{{2x=52}}}
Divide by 2 both sides of the above equation
{{{2x/2=52/2}}}
{{{cross(2)x/cross(2)=cross(52)/cross(2)}}}
{{{x=26}}}



First integer = {{{x+1}}}={{{26+1}}}={{{27}}}
Second integer={{{x+2}}}={{{26+2}}}={{{28}}}
Third integer = {{{x+3}}}={{{26+3}}}={{{29}}}
Fourth integer = {{{x+4}}}={{{26+4}}}={{{30}}}




Check
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The sum of the first three is 54 more than the fourth.
{{{27+28+29=30+54}}}
{{{84=84}}}