Question 563321
(1/3)log54+2log15+(1/3)log32-3log3 
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log(2*27)^(1/3) + log(15^2) + log(8*4)^(1/3) - log(3^3)
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= log(3*2^(1/3)) + log(225) + log(2*4^(1/3)) - log(27)
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= log[3*2^(1/3)*225*2*4^(1/3)/27]
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= log[1350*8^(1/3)/27]
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= log[2700/27]
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= log(100)
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= 10
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Cheers,
Stan H.
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