Question 563236
Let {{{ a }}} = cost of an apple
Let {{{ b }}} = cost of a banana
Let {{{ c }}} = cost of an orange
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given:
(1) {{{ a = 2c }}}
(2) {{{ b + c = a + .1 }}}
(3) {{{ 2c = b + .15 }}}
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(3) {{{ b + .15 = 2c }}}
(3) {{{ b = 2c - .15 }}}
Substitute (1) and (3) into (2)
(2) {{{ b + c = a + .1 }}}
(2) {{{ 2c - .15 + c = 2c + .1 }}}
(2) {{{ 3c - .15 = 2c + .1 }}}
(2) {{{ c = .1 + .15 }}}
(2) {{{ c = .25 }}}
and
(1) {{{ a = 2c }}}
(1) {{{ a = 2*.25 }}}
(1) {{{ a = .5 }}}
and
(3) {{{ b = 2c - .15 }}}
(3) {{{ b = 2*.25 - .15 }}}
(3) {{{ b = .5 - .15 }}}
(3) {{{ b = .35 }}}
The cost of an apple is $.50
The cost of a banana is $.35
The cost of an orange is $.25
check:
(2) {{{ b + c = a + .1 }}}
(2) {{{ .35 + .25 = .5 + .1 }}}
(2) {{{ .6 = .6 }}}
OK
(3) {{{ 2c = b + .15 }}}
(3) {{{ 2*.25 = .35 + .15 }}}
(3) {{{ .5 = .5 }}}
OK