Question 563022
By a change of variables, determine the following integral:

integral ((5x^3 - 3x^2 + 1)^3/2)(5x^2 - 2x) dx
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Let {{{y = 5x^3 - 3x^2 + 1}}}
Then {{{dy = (15x^2 - 6x)dx = 3(5x^2 - 2x)dx}}}
So we can write the integral as:
{{{(1/3)int(y^(3/2),dy)}}}