Question 562913
Triangle ABC: A(x,0); B(x,y); C(2x,0)
Finding AB: {{{sqrt((x-x)^2+(y-0)^2)}}}
{{{sqrt(y^2)}}}
=y
Finding BC: {{{sqrt((2x-x)^2+(0-y)^2)}}}
{{{sqrt(x^2+y^2)}}}
Finding AC: {{{sqrt((2x-x)^2+(0-0)^2)}}}
{{{sqrt(x^2)}}}
=x
Final Steps: a^2+b^2=c^2

{{{(sqrt(x^2))^2+(sqrt(y^2))^2= (sqrt(x^2+y^2))^2}}}
m.ananth@hotmail.ca