Question 562865
{{{6-3r=17}}}
Subtract 6 from both sides of above equation
{{{6-3r-6=17-6}}}
{{{cross(6)-3r-cross(6)=17-6}}}
{{{-3r=11}}}
Divide by -3 both sides of above equation
{{{-3r/-3=11/-3}}}
{{{cross(-3)r/cross(-3)=11/-3}}}
{{{r=11/-3}}}
{{{r=-(3&2/3)}}}


Check
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{{{6-3r=17}}}
Put {{{r=-11/3}}}
{{{6-3(-11/3)=17}}}
{{{6+((3)(11))/3=17}}}
{{{6+(cross(3)(11))/cross(3)=17}}}
{{{6+11=17}}}
{{{17=17}}}