Question 562852
 ={{{x^4+3x^3-x^2+2x-6}}}
 for {{{x=3}}}
 ={{{(3)^4+3(3)^3-(3)^2+2(3)-6}}}

 ={{{81+3(27)-9+6-6}}}
={{{81+81-9+cross(6)-cross(6)}}}
={{{162-9}}}
={{{153}}}