Question 54183
Write as a single logarithm:
{{{2log(6) + log(x) - log(3)}}} 
First, you can apply the "product rule" for logarithms:
{{{log((6)^2) + log((x)) - log((3)) = log(((6)^2(x))) - log(3)}}}
Now apply the "quotient rule" for logarithms:
{{{log(((6^2)(x)))-log(3) = log((((6^2)(x))/3))}}} = {{{log((36x/3)) = log((12x))}}}