Question 562638
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^m\,\cdot\,a^n\ =\ a^{m\,+\,n}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{a^m}{a^n}\ =\ a^m\,\cdot\,a^{-n}\ =\ a^{m\,-\,n}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(a^m\right)^n\ =\ a^{mn}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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