<PRE><B>Question 562621</B>
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For any *[tex \Large n]-gon, the number of diagonals that can be drawn from any one vertex is *[tex \Large n\ -\ 3].  The number of total diagonals is *[tex \Large \frac{n(n\ -\ 3)}{2}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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