Question 561856
16^(2-n)=(1/4)^(n+1)
(2^4)^(2-n)=(4^-1)^(n+1)
2^(8-4n)=4^(-n-1)
2^(8-4n)=4^(-n-1)
2^(8-4n)=2^2^(-n-1)
2^(8-4n)=2^(-2n-2)
8-4n=-2n-2
2n=10
n=5
Check:
16^(2-n)=16^-3=.00024414..
(1/4)^(n+1)=.25^6=.00024414..