Question 562282
at 7:00 am joe starts jogging at 6mi/h . At 7:10 Ken starts off after him. How fast must ken run in order to overtake him at 7:30
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let x=ken's speed (mph)
ken's travel time=7:30-7:10=20 min=1/3 hr
joe's speed=6 mph
joe's travel time=7:30-7:00=30 min=1/2 hr
Both runners covered the same distance
distance=travel time*speed
x*(1/3)=6*(1/2)=3
x=9 mph
ans:
How fast must ken run in order to overtake him at 7:30=9 mph