Question 562263
Hi, let say that log_b is the logarithm with base b function.
Solve log_2(3y+1)=6 for y
We have,
log_2(3y+1)=6
2^(log_2(3y+1))=2^(6)  (exponentiate with respect to the base 2)
3y+1=64
3y=63
y=21

Note that log_b(x) and b^x are inverse functions, so b^(log_b(x))=x