Question 54168
Find two positive real numbers that differ by 1 and have a product of 1
Let one of the numbers be "x" and the other be "x+1"
EQUATION:
x(x+1)=1
x^2+x-1=0
Use the quadratic formula to solve for "x".
x=[-1+-sqrt(1+4)]/2
Since you want positive numbers,
x=[-1+sqrt5}/2 (This is one of the numbers)
x+1=[-1+sqrt5]/2 + 2/2
x+1=[1+sqrt5]/2 (This is the other number)
Cheers,
Stan H.