Question 561917
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This is exactly the same as a "two kinds of coins in a pig bank" problem.  You have to derive an equation that relates to the total NUMBER of the two things and then an equation that relates to the total VALUE of the two things.  In this case, the value is expressed in points, but the idea and the process are the same.


Let *[tex \Large x] represent the number of 8 point questions and *[tex \Large y] represent the number of 10 point questions.  Then the point value of all of the 8 point questions is *[tex \Large 8x] and the point value of all of the 10 point questions is *[tex \Large 10y].  The total NUMBER of questions is 21 and the total point VALUE of all the questions is 200, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ \,x\ +\ \ \ \,y\ =\ \ \,21]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 8x\ +\ 10y\ =\ 200]


Just solve the 2X2 linear system.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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