Question 561602
Solve the equation graphically in the given interval. State each answer correct to two decimals.

x^3 − 12x^2 + 47x − 60 = 0; [−1, 6].
:
They mean you should make a table and graph the the points from x = -1 to +6
For example
x=-1, 
y = -1^3 - 12(-1^2) + 47(-1) - 60
y = -1 - 12 - 47 - 60
y = -120
:
x = +2
y = 2^3 - 12(2^2) + 47(2) - 60
y = 8 - 48 + 94 - 60
y = -6
:
A table, you can complete the table in the same way
 x | y
-------
-1 |-120
 0 |
+1 |
+2 | -6
+3 | 
+4 | 0
+5 |
+6 | +6
:
the graph:
{{{ graph( 300, 200, -4, 10, -150, 100, x^3-12x^2+47x-60) }}}
You can see by the table and the graph, that x intercept, the solution: x=4
:
But when you complete the table, note that x=3, x=5, are also solutions, but not values in between these values, as you can see on the this expanded graph
{{{ graph( 300, 200, -4, 10, -10, 10, x^3-12x^2+47x-60) }}}