Question 561669
{{{ 6x^2 - 11x + 4 }}}
Use quadratic formula
{{{ x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{ a = 6 }}}
{{{ b = -11 }}}
{{{ c = 4 }}}
{{{ x = (-(-11) +- sqrt( (-11)^2-4*6*4 )) / (2*6) }}} 
{{{ x = ( 11 +- sqrt( 121 - 96 )) / 12 }}} 
{{{ x = ( 11 +- sqrt( 25 )) / 12 }}} 
{{{ x = ( 11 + 5 ) / 12 }}}
{{{ x = 16/12 }}}
{{{ x = 4/3 }}}
and, also
{{{ x = ( 11 - 5 ) / 12 }}}
{{{ x = 6/12 }}}
{{{ x = 1/2 }}}
--------------
check:
{{{ ( x - 4/3 )*( x - 1/2 ) = x^2 - (4/3)x - (1/2)*x + 4/6 }}}
{{{ x^2 - (4/3)*x - (1/2)*x + 4/6 = 0 }}}
{{{ 6x^2 - 8x - 3x + 4 = 0 }}}
{{{ 6x^2 - 11x + 4 = 0 }}}