<PRE><B>Question 561171</B>
Susan invested part of her 1800 savings at 9% annum and the remainder at 6% per annum. In one year, the 9% investement earned 102 more than the ^% investement. How much did she invest at each rate?
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Equation:
0.09x - 0.06(1800-x) = 102
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Multiply thru by 100 to get:
9x - 6*1800 + 6x = 10200
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14x = 21000
x = $1500 (amt invested at 9%
1800-x = $300 (amt invested at 6%)
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Cheers,
Stan H.
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