Question 560778
We have a right triangle:


{{{drawing(300,300,0,10,0,10,


triangle(2,2,8,2,8,5),
locate(2.5,2.5,26),
locate(7.5,4.5,64),
locate(4.8,4.5,4.5),
locate(5,2,a),
locate(8.5,3.5,b)

)
}}}


We can use either sine or cosine to find the other two lengths. If you recall the definition of sine, for example, we have


*[tex \LARGE \sin(26^{\circ}) = \frac{b}{4.5}]


*[tex \LARGE \sin(64^{\circ}) = \frac{a}{4.5}]


Then solve for a and b. Make sure your calculator is in degrees instead of radians.