Question 53407
Properties that will be used:
{{{highlight(loga(b^c)=cloga(b))}}}
{{{highlight(loga(b/c)=loga(b)-loga(c))}}}
There are a couple of ways to interpret what you typed so I'm going to show you two possibilities:
{{{log3(sqrt(x)/5)}}}
{{{log3(sqrt(x))-log3(5)}}}
{{{log3(x^(1/2))-log3(5)}}}
{{{highlight((1/2)log3(x)-log3(5))}}}
or if you meant:
{{{log3(sqrt(x/5))}}}
{{{log3((x/5)^(1/2))}}}
{{{(1/2)log3(x/5)}}}
{{{highlight((1/2)(log3(x)-log3(5)))}}}
Happy Calculating!!!