Question 560563


{{{4x-2y=8}}} Start with the given equation.



{{{-2y=8-4x}}} Subtract {{{4x}}} from both sides.



{{{-2y=-4x+8}}} Rearrange the terms.



{{{y=(-4x+8)/(-2)}}} Divide both sides by {{{-2}}} to isolate y.



{{{y=((-4)/(-2))x+(8)/(-2)}}} Break up the fraction.



{{{y=2x-4}}} Reduce.



So the equation {{{y=2x-4}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=2}}} and the y-intercept is {{{b=-4}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-4\right)]