Question 560489
<font face="Times New Roman" size="+2">


I can answer questions about <i><b>angles</b></i>, but for questions about <i><b>angels</b></i>, you need to consult your favorite clergyman.


Let *[tex \Large x] represent the measure of the desired angle in degrees.  Then the measure of the complement of *[tex \Large x] is *[tex \Large 90\ -\ x].  Four times the complement is *[tex \Large 4(90\ -\ x)]  and 15 degrees less than that is *[tex \Large 4(90\ -\ x)\ -\ 15].  And since we know that 15 degrees less than four times the complement IS the angle:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 4(90\ -\ x)\ -\ 15]


Solve for  *[tex \Large x]. 


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>