Question 560245
I'm guessing that the problem first asked to simplify
{{{6z + 1 + 4x^2 - 3y^3 + 7x - 8y^2 + 2x^2 - x + 5z -17}}}
{{{6z+1+4x^2-3y^3+7x -8y^2 +2x^2-x +5z -17}}} = {{{(6z+5z)+(1-17)+(4x^2+2x^2)-3y^3+(+7x-x)-8y^2}}} = {{{(6+5)z+(-16)+(4+2)x^2-3y^3+(7-1)x-8y^2}}} = {{{11z-16+6x^2-3y^3+6x-8y^2}}}
Maybe it would look better writing the terms in a more conventional order as
{{{6x^2+6x-3y^3-8y^2+11z-16}}}
The variables are x, y, and z .
The coefficients is the numbers 6, 6, -3, -8, and 11, that are multiplying the powers of the variables.
The number -16 can be called the constant, or the independent term.