Question 560304
first observation


45 deg
let distance from clif be x
Tan {{{theta}}} = opposite side / afjacent side

tan 45 = h/x
x tan 45 = h

similarly

(x+60)*tan 30 =h

tan30*(x+60)=x * tan 45

x tan 30+ 60 tan 60 = x *tan 45

x tan 30 -xtan 45 = -60 * tan 60


x(tan 30-Tan 45)=-60*tan 30
x=-60*tan 30/(tan 30-Tan 45)
x=-34.64/-0.422
x=82 

tan 45 = h/82
82*tan 45 = h

height of cliff = 82m