<PRE><B>Question 560218</B>

Let
1st  Interger = x+2
2nd   Interger = x+4



Given
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Three times the smaller of two consecutive even integers is the same as -146 minus 4 times the larger integer.
3(x+2)=4(x+4)-146
3x+6=4x+16-146
3x+6=4x-130
3x-4x=-130-6
-x=-136
Multiply by -1 both sides
-x(-1)=-136(-1)
x=136




1st  Interger = x+2 = 136+2 = 138
2nd   Interger = x+4 = 136+4 = 140


Check
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3(138)=4(140)-146
414=560-146
414=414


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