<PRE><B>Question 53851</B>
My problem is (3/4, 8/3) and (2/5, 2/3).
I am supposed to find the slope and put the problem into slope intercept form and then into standard form (Ax+By=C).
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slope = [8/3 - (2/3)]/[(2/5)-(3/4)]
      = 2/(-7/20)
      = -40/7
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2/3 = (-40/7)(2/5)+b
2/3=-80/35 + b
b= (2/3)+(80/35)
b= [70+240]/105
b=2
EQUATION:
y=(-40/7)x+2
To put it in standard form multiply thru by 7 to get:
7y=-40x+14
40x+7y=14
Cheers,
Stan H.



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