Question 560155
F(x) = 4x^3 - 5x + 2x^(1/2). Determine the slope of the tangent when x = 4?
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F'(x) = 12x^2 - 5 + x^(-1/2)
F'(4) = 12*16 - 5 + 1/2
Slope @ x = 4 = 187.5