Question 560127
Take derivative of both sides with respect to x.


*[tex \LARGE 3x^2 + 2y\frac{dy}{dx} = 0] (note that you need dy/dx after 2y because y is a function of x, in which we use the chain rule).
 

Solving for dy/dx, we get


*[tex \LARGE \frac{dy}{dx} = -\frac{3x^2}{2y}]


At x = 2, y = 1, dy/dx = -12/2 = -6.