Question 560070
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Determine the sum of the measures of the internal angles of any pentagon by using the formula *[tex \Large (n\ -\ 2)180] where *[tex \Large n\ =\ 5] because this is a pentagon.  Then determine the constant of proportionality, *[tex \Large k], by adding all of the proportion numbers, that is 4 + 5 + 6 + 7 + 5 and then dividing the sum of the interior angle measures by the sum of the proportion numbers.  Then the measures of the angles are *[tex \Large 4k], *[tex \Large 5k], *[tex \Large 6k], *[tex \Large 7k], and *[tex \Large 5k]  


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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