Question 560042
(1) {{{x - y = 0 }}} 
(2) {{{6x + 5y = -22 }}}
If it doesn't matter what method to use,
the easiest way is by substitution
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Add {{{y}}} to both sides of (1)
(1) {{{ x = y }}}
Now where I see {{{x}}} in equation (2),
I can substitute {{{y}}}
(2) {{{ 6y + 5y = -22 }}}
(2) {{{ 11y = -22 }}}
(2) {{{ y = -2 }}}
Now if I plug this value of {{{y}}} 
back into (1), I get
(1) {{{ x - (-2) = 0 }}}
(1) {{{ x + 2 = 0 }}}
Subtract {{{2}}} from both sides
(1) {{{ x = -2 }}}
So, the solution is (-2,-2)
Here's a plot of the equations that shows this:
{{{ graph( 400, 400, -6, 6, -6, 6, x, (-6/5)*x - 22/5 ) }}}