Question 53949
For "and" compound inequalities the solution is what is true for both inequalities.
{{{(1/3)x>2}}}
{{{3(1/3)x>3*2}}}
{{{(3/3)x>6}}}
{{{x>6}}}
---and----------
{{{(1/4)x>2}}}
{{{4(1/4)x>4*2}}}
{{{(4/4)x>8}}}
{{{x>8}}}
x>6 AND x>8
Only the numbers x>8 satisfies both inequalities.  We use an open circle or a ( to indicate that it doesn't actually = 8.  Shade over all the numbers bigger than 8 (the right side of 8).
<------------------(===========>>
-1,0,1,2,3,4,5,6,7,8,9,10,11,12
Happy Calculating!!!