Question 54089
{{{ abs(x - (y - z)) - abs((x - y) - z) = 0 }}}
{{{ abs(x - (y - z)) = abs((x - y) - z) }}}
{{{ x - (y - z) = (x - y) - z }}}
{{{ x - y + z = x - y - z }}}
{{{ 2z = 0 }}} so {{{z = 0}}}
Since {{{x}}} and {{{y}}} cancel each other out, they can be any real value. On the other hand, {{{z}}} must equal zero.