Question 559518
I think you are trying to go around it the long way to the solution, and getting lost in the woods in between. I would go in there and figure out where you took the wrong fork in the road, but I've learned to be afraid of going through such woods.
I would start from;
{{{log(a,x^2y)}}} = {{{log(a,x^2)}}}+{{{log(a,y)}}} = {{{2*log(a,x)}}}+{{{log(a,y)}}}
You would know what to do then.
It is easier to find your way to the center of a labyrinth if you trace the way back from the center. You do not waste your timr and patience bumping into so many dead ends along the way. Less frustration, less errors. (I learned that the hard way).